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0.16d^2=100
We move all terms to the left:
0.16d^2-(100)=0
a = 0.16; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·0.16·(-100)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8}{2*0.16}=\frac{-8}{0.32} =-25 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8}{2*0.16}=\frac{8}{0.32} =25 $
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